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XSL & XML in FireFox HI, I have an application in IE and I'm moving it to FireFox. There is one section I didn't find match functionality: currSort1DirNodeVal = xsl.documentElement.selectSingleNode("//xsl:param[@name=\"sort1Dir\"]/@select").nodeValue; xsl example is: ...................... <?xml version="1.0" ?> - <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">   <xsl:param name="sortByDummy" select="' '" />   <xsl:param name="sort1By" select="'time'" />   <xsl:param name="sort1Dir" select="'ascending'" />   <xsl:param name="sort1Type" select="'number'" />   <xsl:param name="sort2By" select="' '" />   <xsl:param name="sort2Dir" select="'ascending'" /> .................................. Can you help   thanks :-)   Started By en on Jan 18, 2006 at 5:03:13 AM

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MHenke on Jan 18, 2006 at 5:32:42 AM var currSort1DirNodeVal = xmlDocument.evaluate(("//xsl:param[@name=\"sort1Dir\"]/@select", xmlDocument, null, 9, null).singleNodeValue; Check out document.evaluate() for details.

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